If x, y, z are chosen from the three numbers -3, 1/2 and 2, what is the largest possible value of the expression (x/y) z২?
Created: 6 years ago |
Updated: 1 month ago
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To find the largest possible value of the expression (x/y)z2, we need to consider the maximum and minimum values of each variable x, y, and z.
Given:
- x, y, and z are chosen from the numbers -3, 1/2, and 2.
First, let's find the maximum and minimum values of x/y:
- If x=−3 and y=21, then x/y=−6.
- If x=2 and y=21, then x/y=4.
So, the minimum value of x/y is -6, and the maximum value is 4.
Now, let's consider the maximum and minimum values of z2:
- If z=−3, then z2=9.
- If z=2, then z2=4.
So, the minimum value of z2 is 4, and the maximum value is 9.
To maximize the expression (x/y)z2, we need to choose the maximum value of x/y and the maximum value of z2:
Max value=Max(x/y)×Max(z2)
=4×9
=36
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